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3 years ago

Please answer correctly and no links

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Answer:

4.1x + 29

Step-by-step explanation:

2.3x + 14 + 2x + (-0.2x) + 15

= (2.3x + 2x - 0.2x) + (14 + 15)

= 4.1x + 29

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8, 12, 16,...<br> Find the 31st term.

Ainat [17]

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2 years ago

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Without measuring, how can you determine whether two sides of a polygon are congruent?

Alinara [238K]

Ow... this geometry is sure hard!!
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Wait a second. Nope.
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TWO SIDES!!
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ITT!!
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CONVERSE ITT!!
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Converse Isosceles Triangle Theorem!
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Look at the picture I attached.
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Two angles equal... THE SIDES ADJACENT TO IT EQUAL!!
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PERFECTO!!
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Hope I helped!!

Source: I am learning Honors Geometry, near end of course.

7 0

3 years ago

What is the area of the sector with a central angle of 49° and a radius of 11 cm? Use 3.14 for pi and round your final answer to

olga_2 [115]

Answer:

$\boxed{\text{51.71 cm}^{2}}$

Step-by-step explanation:

If the angle θ is in radians, the formula for the area (A) of a sector of a circle is

A = ½r²θ

If θ is in degrees

$A = \dfrac{1}{2}r^{2}\theta \times \dfrac{\pi \text{ rad}}{180^{\circ}}= \pi r^{2}\times\dfrac{\theta }{360}$

Data:

θ = 49°

r = 11 cm

Calculation:

$\begin{array}{rcl}A& = &3.14\times 11^{2}\times\dfrac{49}{360}\\\\ & = &3.14 \times 121 \times 0.1361\\ & = & \mathbf{51.71}\\\end{array}\\\text{The area of the sector is }\boxed{\textbf{51.71 cm}^{2}}$

4 0

3 years ago

Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who

zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

-Let x be the distance between John and clock tower.

-Let y be the vertical distance from the eyes of the two men standing to the top of the clock tower.

#Taking the right triangle ACD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5$

#Taking the right triangle ABD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5$

#We equate the two yo solve for x and y;

$(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939$