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3 years ago

Part 2 - Survival Kit

Mathematics

1 answer:

valentinak56 [21]3 years ago

8 0

Answer:

Step-by-step explanation:

1. A therapist

2. Strong mental will

3. pencil

4. paper

5. calculator (if allowed)

1. Never trust math

2. x and y are your worst enemies

3. Bring LOTS of paper

4. y=mx+b

1. Don't cheat

2. x is a variable

3. Don't get overly frustrated

One kid got so mad, he started swearing and bashing the book against the table. He got taken out into the hallway where he proceded to punch lockers causing a few teachers to pop their heads out to see if he was alright.

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Elliot ran 4 laps in 209.2 seconds. If he ran at the same

ASHA 777 [7]

Answer: 52.3 seconds

Step-by-step explanation:

209.2 divided by 4

which is 52.3 seconds

6 0

2 years ago

What is the slope of the line tangent to the curve y+2=x22−2siny at the point(2,0)

Kobotan [32]

Answer:

Step-by-step explanation:

hello :

y+2=x²−2siny

calculate y' : y' = 2x -2y'cosy

when x= 2 and y=0 ( at the point(2,0) ) y' is the slope :

y' = 2(2)-2y'cos0 but cos0 =1

y' = 4 -2y'

3y' =4

so : y' = 4/3

3 0

3 years ago

A photograph 5 inches wide by 6 inches high is to be enlarged so that the new height is 20 inches. what will the width of the en

Vika [28.1K]

The new width is 16.6666666667 inches, which can be rounded to 16.7.

Width: 5 ?
Height: 6 20

We know that based on the information provided, the new height is 20 inches.

So, in order to solve, you can cross multiply (5 x 20), which would be 100. Then

divide by 6, to get 16.6666666667 or 16.7.

7 0

3 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.