Given:
The graph of triangle PQR and triangle P'Q'R'.
To find:
The transformation that will map the triangle PQR onto P'Q'R'.
Solution:
From the given graph it is clear that the triangle PQR is formed in II quadrant and its base lies on the negative direction of x-axis.
The triangle P'Q'R' is formed in IV quadrant and its base lies on the positive direction of x-axis.
This is possible it the figure is rotated 180 degrees about the origin.
Therefore, the correct option is A.
Answer:
3x^4 - 13x^3 - x^2 - 11x + 6.
Step-by-step explanation:
x^2-5x+2 x 3x^2 +2x +3
= x^2(3x^2 +2x +3) - 5x(3x^2 +2x +3) + 2(3x^2 +2x +3)
= 3x^4 + 2x^3 + 3x^2 - 15x^3 - 10x^2 - 15x + 6x^2 + 4x + 6
Adding like terms:
= 3x^4 - 13x^3 - x^2 - 11x + 6.
No, they are not similar, because one is 55 degrees and the other is 36 degrees
Answer:
Yes it is.
Step-by-step explanation:
Just multiply everything by 2.
