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Airida [17]
3 years ago
14

Write two alternate functions specified below, each of which simply triples the variable count defined in main. These two functi

ons are: a. Function tripleByValue that passes a copy of count by value, triples the copy and returns the new value.b. Function tripleByReference that passes count by reference via a reference parameter and triples the original value of count through its alias(i.e. the reference parameter)For example, if count
Computers and Technology
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

Following are the code to this question:

#include <iostream>//header file

using namespace std;

int triplebyValue(int count)//defining a method triplebyValue

{

int x=count*3;//defining a variable x that multiply by 3 in the count  

return x;//return value of x

}

void triplebyReference(int& count)//defining a method triplebyReference that hold count variable as a reference in parameter

{

count*=3;//multipling a value 3 in the count variable

}

int main()//main method

{

int count;//defining integer variable

count=triplebyValue(3);//use count to call triplebyValue method

cout<<"After call by value, count= "<<count<<endl;//print count value with message

triplebyReference(count);//calling a method triplebyReference

cout<<"After call by reference, count= "<<count<<endl;//print count value with message

return 0;

}

Output:

After call by value, count= 9

After call by reference, count= 27

Explanation:

In this code two methods "triplebyValue and triplebyReference" are declared, which accepts a count variable as a parameter, and in both multiply the count value by 3 and return its value.

Inside the main method, an integer variable "count" is declared that first calls the "triplebyValue" method and holds its value into count variable and in the next, the method value is a pass in another method that is "triplebyReference", and use print method to print both methods value with a message.

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Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins with a
tekilochka [14]

Answer:

The following are the program to the given question:

import java.util.*;//import package for user input

public class Make  //define class Make

{

public static void main(String[] ask)  //define a main method

{

  Scanner obx = new Scanner(System.in);   //declare the Scanner class object

  int size=obx.nextInt(); //get the size of the array from the user

  int a[]=new int[size]; //declare an integer array with given size

  String word[]=new String[size]; //declare a string array with given size

  for(int i=0;i<size;i++) //set the for loop  

  word[i]=obx.next(); //get string input from the user

  for(int i=0;i<size;i++)   //iterates with the array, increase the count

  {

    for(int j=0;j<size;j++)   //defining a loop to check value

    {

      if(word[i].equals(word[j]))  //use if to check that elements of words          

      a[i]++;//increamenting array size

    }

  }

 System.out.print("\n");  //use print for break line  

  for(int i=0;i<size;i++)//set for loop to print the following result

    System.out.println(word[i]+" "+a[i]);//print value

 }

}

Output:

Please find the attachment file.

Explanation:

  • First, establish the predefined package required and instead define the main class and define the main method within the class and method.
  • Declare the scanner class object and receive an object size in the 'size' variable thru the array.
  • Next create two arrays, the integer type "a" with both the input size given and the string type "word" with the input size supplied.
  • Define the loop for which string array elements are acquired and set two to again for loop, which increases with loop iteration the integer data type array by one.
  • Lastly, set the loop for which this result is printed.

5 0
3 years ago
Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

4 0
3 years ago
Create a new Die object. (Refer to Die.html for documentation.)Create a loop that will iterate at least 100 times. In the loop b
hjlf

Answer:

Java code is given below

Explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

}

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