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3 years ago

What is the value of x?

Mathematics

2 answers:

Delvig [45]3 years ago

4 0

Answer:

46 degrees

Step-by-step explanation:

Sum of the angles in a Tri. =180

63+71=134

180-134=46

Usimov [2.4K]3 years ago

3 0

Answer:

All angles in a triangle sum up to 180 degrees.

So, 63+71+x=180 degrees.

You add like terms: 134, and then add x.

134+x=180 degrees.

Minus x from both sides.

180-134=x.

What do you think x is?

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What is the measure of ∠HFG?<br> (See attachment)

madam [21]

92 degrees

Triangle= 180 degrees
180-60-28= 92

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7 0

3 years ago

Emma receives $7750 and invests it in an account that earns 4% interest copounded continuously, What is the total amount of her

QveST [7]

So your present value is 7750. this is what you have now. they give you the intesrest rate which is 4% and how the amount of year is 5.

recall the formula for a compounded continously is
P×e^(r×t)

the answer is 7750×e^(.04×5)

8 0

3 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

3 years ago

Read 2 more answers

Write an equation perpendicular to the line y = 3x + 5 through the point (6, -5). State your answer as y=mx+b.

liubo4ka [24]

Answer:

y=(-1/3) x - 3

Step-by-step explanation:

A line that is perpendicular to it has a slope that is an opposite reciprocal, which in this case is -1/3. Now you use point slope form which is y-y1=m(x-x1) that would be y+5=-1/3(x-6). Distribute the -1/3 and get y+5= -1/3 x+ 2. Subtract 5 from both sides and get y=-1/3 x - 3

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3 years ago

Jina wanted to study how the area of a rectangle changes with the length if it’s width is fixed. She computed the areas of sever

olganol [36]

Answer:

The domain and the range of the function are, respectively:

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

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3 years ago