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3 years ago

What is the value of x?

Mathematics

2 answers:

Delvig [45]3 years ago

4 0

Answer:

46 degrees

Step-by-step explanation:

Sum of the angles in a Tri. =180

63+71=134

180-134=46

Usimov [2.4K]3 years ago

3 0

Answer:

All angles in a triangle sum up to 180 degrees.

So, 63+71+x=180 degrees.

You add like terms: 134, and then add x.

134+x=180 degrees.

Minus x from both sides.

180-134=x.

What do you think x is?

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In the figure, a pair of parallel lines Is cut by a transversal. What kind of angle are angles A and C?

Sonbull [250]

Answer: Angles A and C are vertical angles.

Step-by-step explanation:

5 0

3 years ago

Draw a conclusion is the statement below always sometimes or never true give at least two examples to support your reasoning the

hodyreva [135]

It's sometimes true.

One example is the least common multiple of 2 and 3 is 6, which is their product.

But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.

Ergo, it is only sometimes true.

3 0

3 years ago

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago

Factor using the trinomial<br> 10.<br> X2 + 13x + 12

Rudik [331]

Answer:

Factoring the trinomial: $x^2+13x+12$ we get the factors $\mathbf{(x+1)(x+12)}$

Step-by-step explanation:

We need to factor the trinomial: $x^2+13x+12$

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

$x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)$

So, Factoring the trinomial: $x^2+13x+12$ we get the factors $\mathbf{(x+1)(x+12)}$

8 0

3 years ago

9,13,43,55 what is the mean absolute deviate (MAD) of their ages

lisov135 [29]

Answer:

The mean absolute deviation of this data $\{9,13,43,55\}$ is $MAD =19$ .

Step-by-step explanation:

The mean absolute deviation (MAD) of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset.

The steps to find the MAD include: