10^-2 x 6^-2 please help
1 answer:
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First we need to see in which quadrant 11pi/6 lies And it lies in fourth quadrant. And to find the reference angle in the fourth quadrant, we need to subtract the given angle from 2 pi . For e.g if the angle is 5pi/3, then the reference angle is 2pi - (5pi/3) = pi/3 .
So for the given question, reference angle of 11pi/6 is
And that's the required reference angle .
The radius of a sphere that has a surface area of 12.56in2 would turn out to be:
4
r²
4