The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
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Answer:
34000cm or 340m
Step-by-step explanation:
We have to find total surface area.
dimensions of 1 wooden box =
l = 1m = 100cm
b = 80cm
h = 25cm
∴ In the case of 2 =
l = 100cm
b= 80cm
h = 25 + 25 = 50cm
T.S.A = 2(lb + lh + bh)
= 2(100*80 + 100*50+ 80*50)
= 2(8000+5000+4000)
= 2*17000
= 34000cm
= 340m
Answer:
the right answer is -5 (B)
Step-by-step explanation:
-(-5) +5(-5+2)
5 + -15 = -10
As shown in the figures given :
For Figure 1 : perimeter = 8 units [As can be seen in the figure]
For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units [since 1 side is common ]
For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units [since 2 sides is common ]
If one more octagon is added
then perimeter = 8 × 4 - 3 = 29 units [since 3 sides will be common ]
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417