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Tems11 [23]
3 years ago
6

Answer this question to get marked as brainliest!!!!

Mathematics
2 answers:
Brut [27]3 years ago
8 0

Answer:

74 Degrees

Step-by-step explanation:

Mistakes were made when i said 37

notka56 [123]3 years ago
5 0

Answer:

\Huge\boxed{74}

Step-by-step explanation:

Hello There!

First things first, we need to find the value of x

If you didn't know the measures of supplementary angles add up to equal 180 so we can use this equation to solve for x

180 = 2x + 3x - 5

step 1 combine like terms

2x + 3x = 5x

now we have

180 = 5x - 5 step 2 add 5 to each side

-5 + 5 cancels out

180 + 5 = 185

now we have 185 = 5x

step 3 divide each side by 5

5x/5=x

185/5=37

we're left with x = 37

Now we want to plug in 37 into x for angle A

angle a = 2(37)

2*37=74

so we can conclude that angle A = 74

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Answer: -54

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3 0
3 years ago
Wyd? Can u help with these plz
N76 [4]

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6 0
4 years ago
Read 2 more answers
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gayaneshka [121]

Answer:

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Step-by-step explanation:


6 0
3 years ago
How do you use proportions to solve percent problems​
exis [7]

Answer:

Step-by-step explanation:

EXAMPLE #1:

What number is 75% of 4?   (or   Find 75% of 4.)

The PERCENT always goes over 100.

   (It's a part of the whole 100%.)

4 appears with the word of:

   It's the WHOLE and goes on the bottom.

A proportion showing one fraction  with PART as the numerator and 4 as the denominator equal to another fraction with 75 as the numerator and 100 as the denominator.

We're trying to find the missing PART (on the top).

In a proportion the cross-products are equal:   So 4 times 75 is equal to 100 times the PART.

The missing PART equals 4 times 75 divided by 100.

(Multiply the two opposite corners with numbers; then divide by the other number.)

4 times 75 = 100 times the part

300 = 100 times the part

300/100 = 100/100 times the part

3 =   the part

A proportion showing the denominator,  4, times the diagonally opposite 75; divided by  100.

7 0
3 years ago
Can anyone help me plzzzzz /deltamath
irakobra [83]
ANSWER: square root of 10

Rule: Pythagorean Theorem (a^2 + b^2 = c^2; side^2 + second side^2 = hypotenuse^2)

(substitute the missing side w/ a variable)
x^2 + 7^2 = (sqrt. 59)^2
x^2 + 49 = 59
x^2 = 10
x = sqrt. 10
7 0
3 years ago
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