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Lady_Fox [76]
3 years ago
9

An object has a volume of 7cm³ and a mass of 56g. What is its density in g/cm³?

Mathematics
1 answer:
Nastasia [14]3 years ago
5 0

Answer:8

Step-by-step explanation;Since you want to find the density but you already have the mass you do the inverse operation and divdie 56 by 7 and get 8.

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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
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Consider the graph of the linear equation 2x - 5y = 10.
jeyben [28]

Answer:

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y-intercept= (0,-2)

Slope= 2/5

Step-by-step explanation:

7 0
3 years ago
Write the related facts for the set of numbers.<br> 3,7,21
STALIN [3.7K]
They all have either a common factor, common multiple, LCF, GCF, LCM, or GCM. The G and L stand for greater and least.
4 0
3 years ago
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Eddie built the ramp shown to train his puppy to do tricks. What is the surface area of the ramp. The dimensions are 20,20,20,23
mamaluj [8]

Answer:

3775 in²

Step-by-step explanation:

The surface area of the ramp :

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 25 * 23 = 575 in²

Bottom rectangle = 60 * 23 = 1380 in²

For the trapezium: (front and rear)

1/2 (base 1 + base 2) * height

Base total = 20+ 20+ 20= 60

1/2(60)*15 = 450 in²

Total surface Area :

(460 + 460 + 575 + 1380 + 450 + 450) in² = 3775 in²

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Answer:

644

Step-by-step explanation:

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