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Novosadov [1.4K]

3 years ago

7

A weather station on the top of a mountain reports that the temperature is currently 0 and has been falling at a constant rate o

f 3 degrees per hour. Find each temperature. What was the temperature: 1 hour ago? degrees 3 hours ago? degrees

1 answer:

dlinn [17]3 years ago

6 0

Answer:

Because I SAVAGE

GK IT"S WRONG AHAHHAHHAHA

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Prove the divisibility of the following numbers:<br><br> 51^7-51^6 by 25

vampirchik [111]

To prove the divisibility lets expand each number first to get the complete picture of the problem

51^7 = 8.974106779 . 10^11

51^6 = 1.75962878 . 10^10

(51^7 - 51^6) = 8.974106779 . 10^11 - 1.75962878 . 10^10

= 8.798143901. 10^11

$\frac{8.798143901. 10^11}{25}$

= 3.51925756. 10^10

That is the answer expressed in scientific notation

= 35192575600

Which means the divisibility is proven

8 0

3 years ago

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The linear equation x=5 would be a graph of a..

Lelechka [254]

Thw answer to your Problem would be A

7 0

4 years ago

A book is 21 centimeters long, how long is this in meters?

Gnesinka [82]

Answer:

0.21 meters :)

Step-by-step explanation:

4 0

3 years ago

If a solution has 24g of sugar in 130ml of water, what is its concentration?

Jobisdone [24]

Answer: concentration = 15.58%

Step-by-step explanation:

Given: mass of sugar = 24 g = 24 ml [ ∵ 1 g = 1 ml]

Volume of solution = Quantity of water + quantity of solute

= 130 +24 ml

= 154 ml

Concentration = $\dfrac{mass\ of\ solute}{Volume\ of\ solution}\times100$

$=\dfrac{24}{154}\times 100\\\\\approx15.58\%$

Hence, the concentration =15.58%

3 0

3 years ago

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

3 years ago