(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Let x = Barbie's number
1/3 x -20 = 72
1/3 x = 92
x = 92*3=276
Answer:
No, u keep going around and answering questions with sorry i don't know the answer and its pising me off, so just stop before you get your account reported too many times and end up getting banned from answering questions.
Answer:
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Step-by-step explanation:
9514 1404 393
Answer:
142
Step-by-step explanation:
The first term of this arithmetic sequence is -10. The common difference is -8-(-10) = 2. The n-th term is ...
an = a1 +d(n -1)
an = -10 +2(n -1) = 2n -12
Then the 77th term is ...
a77 = 2(77) -12 = 154 -12
a77 = 142
The 77th term is 142.
