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Oksi-84 [34.3K]
3 years ago
12

Please help thank you so much!!!!!

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

Csc(60)

sin(330)

-4cot(-45)

Step-by-step explanation:

The cosen típic is not mant for use With this type of problem.

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Use the two frequency tables to compare the life expectancy of men and women from 20 randomly selected countries. Include an ove
sweet [91]

Answer:

<em>conclusion : Life expectancy of women > Life expectancy of men </em>

Step-by-step explanation:

A) Mean life expectancy of women

from the attached table

mean life expectancy of women = ∑fx / ∑f

∑fx = 1523

∑f = 20

mean = 1523 / 20 = 76.15

The line graph shows a negatively skewed distribution

B) Mean life expectancy of Men

from the attached table

mean life expectancy of Men = ∑fx / ∑f

∑fx = 1432

∑f = 20

mean = 1432 / 20 = 71.6

<em>conclusion : Life expectancy of women > Life expectancy of men </em>

3 0
3 years ago
For which pair of points can you use this number line to find the distance?
Brilliant_brown [7]

Answer:

(2,0) and (2,3)

Step-by-step explanation:

3 0
3 years ago
DUE TODAY AT 4 HELP ME
liq [111]

Answer:

The bar over the 9 means that the nine is repeating itself

7 0
3 years ago
Read 2 more answers
What are the zeros of the function? <br> f(x)=x^2+7x-60
blsea [12.9K]

x^2+7x-60 =0\\x^2-5x+12x-60=0\\x(x-5)+12(x-5)=0\\(x+12)(x-5)=0\\x=-12 \vee x=5

5 0
3 years ago
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Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10
Fofino [41]

Answer:

k = -2

Step-by-step explanation:

x     -1   0   2     5

f(x)  2   0  -4  -10

ƒ(x) = kx

Substitute a pair of values for x and ƒ(x)

-10 = k×5

Divide each side by 5

k = -2

The constant of variation k = -2.

8 0
3 years ago
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