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3 years ago

Simplify fully the question above

Mathematics

1 answer:

Arisa [49]3 years ago

3 0

Answer:

what question I don't see anything

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Archaeologists attempt to reconstruct past ways of life by examining preserved bones, the ruins of buildings, and artifacts such

jok3333 [9.3K]

I thing b I'm not sure tho

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3 years ago

<img src="https://tex.z-dn.net/?f=8x%20%2B%204%20%3D%205x%20-%2011%20" id="TexFormula1" title="8x + 4 = 5x - 11 " alt="8x + 4 =

Anon25 [30]

8x + 4 = 5x - 11

Subtract 5x from both sides:
3x + 4 = -11

Subtract 4 from both sides:
3x = -15

Divide both sides by 3:
x = -5

Answer : x = -5

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3 years ago

The table shows the number of tennis balls that can fit into a given number of cans each can holds the same number of balls fill

Pepsi [2]

Step-by-step explanation:

i could have answer it if you have given the table too!

that's it ....

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2 years ago

1. Find the length of the missing side:<br>35cm<br>60.5°

Tems11 [23]

Answer:

23.52 cm

Step-by-step explanation:

4 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago