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kobusy [5.1K]
4 years ago
8

Tommy and Zach are starting out at the same position. Tommy runs north at 3 miles per hour and Zach starts to run east 2 hours l

ater at the rate of 4 miles per hour. How long until Tommy and Zach are 8 miles apart?
Mathematics
2 answers:
brilliants [131]4 years ago
5 0

Zach=2 hours Tommy= 3 1/2 hours

oksano4ka [1.4K]4 years ago
3 0
Okay, Tommy runs in a positive y direction at 3mph, and his position can be expressed as:

T=3t

Then Zach starts running two hours later at 4mph and his position can be expressed as:

Z=4(t-2)=4t-8

The distance between Tommy and Zach can be expressed as the hypotenuse length of a right triangle with the distances for Tommy and Zach being the lengths of the sides...

d^2=T^2+Z^2

d^2=(3t)^2+(4t-8)^2

d^2=9t^2+16t^2-64t+64

d^2=25t^2-64t+64, and we want to know when they are 8 miles apart

25t^2-64t+64=8^2

25t^2-64t+64=64

25t^2-64t=0

25t(t-2.56)=0

So 2.56 hours after Tommy started running they will be 8 miles apart.

To be clear though, this is the time Tommy spent running, or the time that elapsed since Tommy started running.  Zach has only been running for 0.56 hours.  So if they are looking for the time Zach ran it is 0.56 not 2.56 hours.
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0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store
g100num [7]

This question is incomplete, the complete question is;

The Millennium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20.00 plus 6.00% TAX. The cannon emits protons at a speed of 0.741 c with respect to the ship.

What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction?  0.911 ANS .

What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction?

(Use positive sign for the forward direction, and negative for the backward direction.)

Answer:

A)

the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

B)

the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Step-by-step explanation:

Given that;

speed of ship u = 0.525C

speed of proton emission v = 0.741C

Now When Cannon is shot in Forward Direction

Relativistic speed S is Calculated as;

S = (u+v) / ((1 + (uv))/c²)

we substitute (0.525 + 0.741 )C / ((1 + (0.525 × 0.741) C)/c²)

the C² cancel each other

so we have

S = 1.266 / 1.389925

S = 0.9108 ≈ 0.911c

Therefore the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

When Cannon is shot in Backward  Direction

Relativistic speed S is Calculated as;

S = ( u – v ) / ( 1 – uv / c ²)

S =  (0.525 - 0.741) C / ((1 - (0.525 × 0.741) C)/c²)

the C² cancel each other

so S = -0.216 / 0.610975

S = -0.3535c

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Therefore the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

<em>Use the Pythagorean Thoerem</em>

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