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iVinArrow [24]
3 years ago
13

the inequality below compares two rational numbers -6/18-17/27 if two numbers were plotted as values on a horizontal number line

.which statement is true?​
Mathematics
1 answer:
Lyrx [107]3 years ago
6 0

Correct question is;

The inequality below compares two rational numbers.

-6/18 > -17/27

If the two numbers were plotted as values on a horizontal number line, which statement would be true?

A) Both numbers lie to the right of 0, and −6/18 lies to the left of −17/27

B) Both numbers lie to the left of 0, and −6/18 lies to the left of −17/27

C) Both numbers lie to the right of 0, and −6/18 lies to the right of −17/27.

D) Both numbers lie to the left of 0, and −6/18 lies to the right of −17/27

Answer:

Option D

Step-by-step explanation:

In writing inequality on a number line, any number that is negative will lie to the left of zero while any number that is positive will lie to the right of zero.

Now in this case they are both negative, so they will lie to the left of zero.

Also, the number that is greater will lie to the right of the lesser number.. In this case -6/18 > -17/27. Thus, -6/18 will lie to the right of -17/27

Thus, option D is correct

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zavuch27 [327]
I think it’s Choice A
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An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
3 years ago
Explain your answer please.
andriy [413]
Just do length x width x height
7 0
3 years ago
Suppose p(a) = 0.40 and p(a 
sveticcg [70]
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

P(A\cup B)+P(A\cap B)=P(A)+P(B)


For parts (a) and (b), you're given everything you need to determine P(B).

For part (c), if A and B are mutually exclusive, then P(A\cap B)=0, so P(A\cup B)=P(A)+P(B). If the given probability is P(A\cup B)=0.55, then you can find P(B)=0.15. But if this given probability is for the intersection, finding P(B) is impossible.


For part (d), if A and B are independent, then P(A\cap B)=P(A)\cdot P(B).
8 0
3 years ago
Write a subtraction that will give the same difference as 15-7
Georgia [21]
15 - 7 = 8 so there are many you can do like:
16 - 8 = 8
20 - 12 = 8
22 - 14 = 8
and so on, there are many.




8 0
3 years ago
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