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Free_Kalibri [48]
3 years ago
15

5x 2 1/8 Can you explain please

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:It is in the DMAS rule

Step-by-step explanation:5*21/8

=5*2

=10

pls mark me brainliest

:)

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Pls help me im sooo stuck on math​
Alla [95]
87

You can add up the angles that are labeled(73,110,and 90 because of the right angle) and get 273.

For a quadrilateral, all of the angles add up to 360.

So, subtract 360-273.

You get 87.

Hope this helps:)
8 0
3 years ago
6. Darcy jogs 3 km in 20 min.
SOVA2 [1]

Answer:

a) 9 km

b) 18 km

c) She runs at a constant speed of 9 km/h

Step-by-step explanation:

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3 years ago
How do rigid motions affect a given figure?
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Can you post a picture about the question
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3 years ago
. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
What’s the area and perimeter for this problem?
notka56 [123]

Answer:

the area of the triangle is 41

the perimiter of the triangle is 33.25

Step-by-step explanation:

4 0
2 years ago
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