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3 years ago

The slope of the line shown above

Mathematics

1 answer:

IRINA_888 [86]3 years ago

7 0

Answer:

huh

Step-by-step explanation:

there is no attachment my guy

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Write this equation in Perfect Square form. y=x²+12x-8

Otrada [13]

Answer:

Step-by-step explanation:

I need to get this to 20 words and i feel bad but i am not doing this use a god dam calculater.. ok im at 20 words bye now

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3 years ago

Write an equation to represent the given problem.

stepladder [879]

Answer:

x + x(0.97)=33300

Step-by-step explanation:

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3 years ago

Which of the following sets represents the domain of the function shown?

BartSMP [9]

The domain is 2, 15, 21, 24

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3 years ago

Differentiate x^2 e^x logx

zimovet [89]

Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

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3 years ago

What is the value of the expression shown below?

Gwar [14]

I think the answer is 8 1/8

7 0

3 years ago