Yes I do believe that is correct!
Use the distributive property to express the sum of the 2 whole numbers 15 and 30 with common factors as a multiple of two whole numbers with a sum of no common factor the solution would be (15 plus 30) = 15(1+2)
Answer:
A
Step-by-step explanation:
Given
2k² - k - 3
Consider the factors of the product of the k² term and the constant term which sum to give the coefficient of the k- term.
product = 2 × - 3 = - 6 and sum = - 1
The factors are + 2 and - 3
Use these factors to split the k- term
2k² + 2k - 3k - 3 ( factor the first/second and third/fourth terms )
= 2k(k + 1) - 3(k + 1) ← factor out (k + 1) from each term
= (2k - 3)(k + 1) → A
Answer:
f(2)=5, f(-2)=-7
Step-by-step explanation:
Step 1 : f(2)=3(x)-1
f(2)=5
Step 2 : f(-2)=3(x)-1
f(-2)=-7