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FrozenT [24]
2 years ago
15

PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE

Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

Problem 1

<h3>Answer:  6.7</h3>

----------------

Work Shown:

The two points are (x_1,y_1) = (1,-2)  and (x_2,y_2) = (4,4)

Apply the distance formula to get the following

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer:  3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points (x_1,y_1) = (3,1) and (x_2,y_2) = (5,-2)

The distance between them is...

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\

This distance is approximate.

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A group of friends was working on a student film. They spent $330 on costumes, which was 55% of their total budget. What was the
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What is the value of x?<br> (3x + 50)<br> Enter your answer in the box.<br> (6x - 10<br> x =
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2 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
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\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
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3 years ago
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