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FrozenT [24]
2 years ago
15

PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE

Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

Problem 1

<h3>Answer:  6.7</h3>

----------------

Work Shown:

The two points are (x_1,y_1) = (1,-2)  and (x_2,y_2) = (4,4)

Apply the distance formula to get the following

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer:  3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points (x_1,y_1) = (3,1) and (x_2,y_2) = (5,-2)

The distance between them is...

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\

This distance is approximate.

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Given

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the line y = - 5x+4 and point (1,2)

The equation of the Parallel line to the given line is  ax+by+k=0

Given straight line  5x + y -4 =0

The equation of the Parallel line to the given line is  5x+y+k=0

This line passes through the point (1,2)

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<u>Final answer:-</u>

The equation of the Parallel line to the given line is  5x+y-7=0

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