I NEED HELP WITH THIS ASAP THIS IS PART OF MY GRADE (no its not lol) THIS IS SOOO HARD CAN YOU ANSWER 2-2+2 OMG ITS HARD RIGHT??
2 answers:
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Answer: Provided.
Step-by-step explanation: We are given two lines 'h' and 'k' which are parallel to each other. Also, there is another line 'j' that is perpendicular to line 'h'.
We are to prove that line 'j' is perpendicular to line 'k'.
Let, m, n and p be the slopes of lines 'h', 'k' and 'j' respectively.
Now, since line 'h' and 'k' are parallel, so their slopes will be equal. i.e., m = n.
Also, lines 'h' and 'j' are perpendicular, so the product of their slopes is -1. i.e.,
m×p = -1.
Hence, we can write from the above two relations
n×p = -1.
Thus, the line 'j' is perpendicular to line 'k'.
Proved.
If you're asking for extrema, like the previous posting
well
like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points
and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum
well
like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points
and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum
Answer:
Step-by-step explanation:
Each point of function b(x) is shifted by rule
x -----> ( x - 2 )
and
y -----> (y + 3)
( - 1.5, 0) ------> (- 3.5, 3)
(- 1, - 1) -----> ( - 3, 2)
(0, - 2) ------> ( - 2, 1)
(1, - 1) -----> ( - 1, 2)
(2, 3) -----> (0, 6)
(4, 7) -----> (2, 10)
......
