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sergeinik [125]
3 years ago
7

The sum of three numbers is 84. The second number is 2 times the third.The third number is 8more than the first. What are the nu

mbers?
Mathematics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

let the the first number X,

second number be 2×(8x) or. 16x

third number be 8x

equation 1 ,

X + 16x + 8x = 84

or. 25x = 84

or. x = 84 ÷ 25 = 3.36

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Seascapes rent small fishing boats for a day-long fishing trips. each boat can carry only 1200 lb of people and gear for safety
solmaris [256]

A. We are given that each person weighs 150 lb, each gear per person weighs 10 lb, and a total of 200 pounds of gear for the boat itself.

Since each person only carries one gear, therefore total weight per person in 160 lb (weight of person + weight of gear).

So let us say that x is the number of persons, the inequality equation is:

 

160 x + 200 ≤ 1200

 

 

B. There are three groups that wish to rent the boat.

> Solve the inequality equation when x = 4

160 (4) + 200 ≤ 1200

840 ≤ 1200           (TRUE)

 

> Solve the inequality equation when x = 5

160 (5) + 200 ≤ 1200

1000 ≤ 1200         (TRUE)

 

> Solve the inequality equation when x = 8

160 (8) + 200 ≤ 1200

1480 ≤ 1200         (FALSE)

 

So only the 4 people group and 5 people group can safely run the boat.

 

 

C. Find the maximum number of people that may safely use the boat, solve for x:

 

160 x + 200 ≤ 1200

160 x ≤ 1000

x ≤ 6.25

 

Therefore the maximum number of people that can safely use the boat is 6 people.

3 0
3 years ago
What are three ratios for 5/9
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2 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

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3 years ago
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