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sergeinik [125]
3 years ago
7

The sum of three numbers is 84. The second number is 2 times the third.The third number is 8more than the first. What are the nu

mbers?
Mathematics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

let the the first number X,

second number be 2×(8x) or. 16x

third number be 8x

equation 1 ,

X + 16x + 8x = 84

or. 25x = 84

or. x = 84 ÷ 25 = 3.36

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Which of the following has a positive value? sec (2pi/3) tan (2pi/3) cos (2pi/3) csc (2pi/3)
Darya [45]

Answer:  D) csc (2π/3)

<u>Step-by-step explanation:</u>

2π/3 is in Quadrant II

Quadrant II has a negative x-value and a positive y-value.

x-values are: cos & sec

y-values are: sin & csc

tan = y/x so will be negative in Quadrant II

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3 years ago
To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 ka
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Answer:

The cost of one bear is <u>$47,000</u>.

Step-by-step explanation:

The question is incomplete and the data is missing so the complete question with data is below with attached files:

To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 karat teddy bears", are made mohair,silk and gold thread and have diamond and sapphire eyes.

The chart shows the approximate cost of " 125 teddy bears". Based on the pattern, how much does one bear cost?

Now, to get the cost of one bear.

So, we solve it by using unitary method:

If 4 bears cost = $188,000.

Then 1 bear cost = 188000\div 4=47000

Thus, cost of one bear is $47,000.

Now, we check it by using another pattern of the data:

If 7 bears cost = $329,000.

Then 1 bear cost = 329000\div 7=47000.

Hence, the cost of one bear is $47,000.

Therefore, the cost of one bear is $47,000.

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3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
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L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

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There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

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3 years ago
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HELLO

Rodger my good friend walked 1200 meters.

Kilo- 1000m

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3 years ago
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