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2 years ago

Simplify: (x+3)(x-3)-(1-9)

Mathematics

2 answers:

Fiesta28 [93]2 years ago

8 0

Answer:

x^2-1

Step-by-step explanation:

xxMikexx [17]2 years ago

3 0

Answer:

Step-by-step explanation:

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Use the image to solve

elixir [45]

The answer is

140 degree

3 0

3 years ago

Which of the following is an even function? A.f(x) =(x-1)^2 b. F(x)=8x c.f(x) =x^2-x d.f(x)=7

pentagon [3]

Answer:

Step-by-step explanation:

A.f(x) =(x-1)^2 is even because of that even exponent, 2.

b. F(x)=8x is odd because x has the exponent 1.

c.f(x) =x^2-x is neither even nor odd

d.f(x)=7 is even because the exponent is even: 7^0

4 0

3 years ago

Please Evaluate 27 times ( 1/3) to the 3 power. A). 1 B). 3 C). 9 D). 27

topjm [15]

Answer:

you want to follow PEMDAS so you would multiply 27 by 1/3 to get 81.003, which you would round to 81, then you would multiply 8 to the third power and you would get 512.

Step-by-step explanation:

27(1/3)^3

81^3

512

7 0

3 years ago

Really really need help on ONE math graph question.

Nat2105 [25]

The answer is -3.5, 0.5

7 0

3 years ago

Please help!!!

Leto [7]

Answer:

- The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

This is:

$cos\alpha=\frac{adjacent}{hypotenuse}$

In this case:

$\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC$

Therefore, the scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ , and solve for the distance between the Sun and the shooting star "AC":

$cos(x\°)=\frac{y}{AC}$

$AC=\frac{y}{cos(x\°)}$

3 0

3 years ago

Read 2 more answers