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notsponge [240]
3 years ago
10

Please help me........

Mathematics
2 answers:
NeX [460]3 years ago
7 0

Answer:

Step-by-step explanation:

j because of the alzemiers algorithim

ikadub [295]3 years ago
4 0

Answer:

Select F

Step-by-step explanation:

G is right triangle, not isoceles

H is also true

J is not true

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6

Step-by-step explanation:

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craig has a coin and a number cube.The number cube is labeled 1-6.He flips the coin once and rolls the number cube once.What is
lilavasa [31]

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3/12

Step-by-step explanation:

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3 years ago
Tim bought a pen for $2.25 a pencil for $0.59 a notebook for $6.49 in a highlighter for $1.49 he use the coupon that gave him $5
Margarita [4]
2.25 + 0.59 + 6.49 + 1.49 = 10.82 dollars
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3 0
3 years ago
Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com
lora16 [44]
A)

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}

b)

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}

c)

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}
7 0
3 years ago
N squared equals 196m
xxTIMURxx [149]

Answer:

N= 38,416

Step-by-step explanation:

196×196 = 38,416. square root of 38,416 is 196 therefore N= 38,416

7 0
3 years ago
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