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2 years ago

Which of the following is the algebraic expression that best describes the height y, if x is the width?

Mathematics

1 answer:

Musya8 [376]2 years ago

4 0

I think the answer is a

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What is the value of 2(x+y)² when X=3 and Y=4 ?

otez555 [7]

Answer:

Step-by-step explanation:

Step 1: Define

2(x + y)²

x = 3

y = 4

Step 2: Substitute and Evaluate

2(3 + 4)²

2(7)²

2(49)

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3 years ago

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What is the area of a parallelogram that has a base of 12 3/4 inches and a height of 2 1/2 inches

wolverine [178]

12, 3/4=12.75. 2, 1/2=2.5. All you have to do is multiple base * height to get your answer. so 12.75*2.=31.875.

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3 years ago

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Solve for n

uranmaximum [27]

12n+32=10n+20
-10n -10n
2n+32=20
-32 -32
2n= -12
2 2
N = -6

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3 years ago

I WILL GIVE BRAINLIEST!!!

dlinn [17]

Answer:

p=2x^3+3x

Step-by-step explanation:

no explanation math papa

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2 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

9 months ago