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LiRa [457]
3 years ago
11

What is the value of mc013-1.jpg? –4 –2 2 4 the pic is the .jpg

Mathematics
2 answers:
vredina [299]3 years ago
8 0
Hello there. hope i have answered your question on the above picture.

Black_prince [1.1K]3 years ago
4 0
The answer is 2 if your dividing if not comment me and ill answer it
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Please help me asap!!
Sauron [17]
I believe the answer is C
7 0
3 years ago
Try to simplify 72/6+85/6
Reil [10]
72/6+ 85/6
= (72+ 85)/6
= 157/6
= (156+1)/ 6
= 156/6+ 1/6
= 26+ 1/6
= 26 1/6

The final answer is 26 1/6~
4 0
3 years ago
Read 2 more answers
What is the factored form of this expression? 4t2 − 27t + 18
seraphim [82]

Answer:

(4t − 3) (t − 6)

Step-by-step explanation:

Using AC method:

Given a quadratic ax² + bx + c, find factors of ac that add up to b.  Divide those factors by a and reduce.  The denominators become the coefficients and the numerators become the constants.

Here, a = 4, b = -27, and c = 18.

ac = 4 × 18 = 72

Factors of 72 that add up to -27: -3 and -24

Divide factors by a: -3/4 and -24/4

Reduce: -3/4 and -6/1

So the factored expression is:

(4t − 3) (t − 6)

5 0
4 years ago
The tickets for an upcoming ballet cost $54 per person. Mrs. Anastos wants to purchase 16 tickets for her friends. What
MissTica

Answer:

the answer is $864 pls give brainliest

Step-by-step explanation:

5 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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