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Helen [10]
3 years ago
14

Paula has 54 stickers and 36 pencils that she wants to put in bags. All the bags will have an equal number of stickers and an eq

ual number of pencils. What is the greatest number of bags she can make and have no stickers and no pencils left over
Mathematics
2 answers:
Andrei [34K]3 years ago
7 0
The answer is 18 bags
m_a_m_a [10]3 years ago
3 0

Answer:

18 bags

Step-by-step explanation:

We need to find the greatest common factor

Break each number into its prime components

54 = 9*6 = 3*3*3*2

36 = 6*6 = 3*2*3*3

Find the common terms

3*3*2

18

The greatest common factor is 18

She can make 18 bags

It will contain  3 stickers and 2 pencils

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Marina simplified the expression 4x + 5 (-4x -b) - (x -2) to be -17x -8.
S_A_V [24]

Answer:

C.)

Step-by-step explanation:

4x -20x -5b -x +2=-17x -8

-17x-5b+2=- 17x-8

+17x +17x

-5b +2= -8

-2 -2

-5b = -10

b= 2

7 0
3 years ago
Grades on a standardized test are known to have a mean of 1000 for students in the United States. The test is administered to 45
vovikov84 [41]

Answer:

a. The 95% confidence interval is 1,022.94559 < μ < 1,003.0544

b. There is significant evidence that Florida students perform differently (higher mean) differently than other students in the United States

c. i. The 95% confidence interval for the change in average test score is; -18.955390 < μ₁ - μ₂ < 6.955390

ii. There are no statistical significant evidence that the prep course helped

d. i. The 95% confidence interval for the change in average test scores is  3.47467 < μ₁ - μ₂ < 14.52533

ii. There is statistically significant evidence that students will perform better on their second attempt after the prep course

iii. An experiment that would quantify the two effects is comparing the result of the confidence interval C.I. of the difference of the means when the student had a prep course and when the students had test taking experience

Step-by-step explanation:

The mean of the standardized test = 1,000

The number of students test to which the test is administered = 453 students

The mean score of the sample of students, \bar{x} = 1013

The standard deviation of the sample, s = 108

a. The 95% confidence interval is given as follows;

CI=\bar{x}\pm z\dfrac{s}{\sqrt{n}}

At 95% confidence level, z = 1.96, therefore, we have;

CI=1013\pm 1.96 \times \dfrac{108}{\sqrt{453}}

Therefore, we have;

1,022.94559 < μ < 1,003.0544

b. From the 95% confidence interval of the mean, there is significant evidence that Florida students perform differently (higher mean) differently than other students in the United States

c. The parameters of the students taking the test are;

The number of students, n = 503

The number of hours preparation the students are given, t = 3 hours

The average test score of the student, \bar{x} = 1019

The number of test scores of the student, s = 95

At 95% confidence level, z = 1.96, therefore, we have;

The confidence interval, C.I., for the difference in mean is given as follows;

C.I. = \left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm z_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

Therefore, we have;

C.I. = \left (1013- 1019  \right )\pm 1.96 \times \sqrt{\dfrac{108^{2}}{453}+\dfrac{95^{2}}{503}}

Which gives;

-18.955390 < μ₁ - μ₂ < 6.955390

ii. Given that one of the limit is negative while the other is positive, there are no statistical significant evidence that the prep course helped

d. The given parameters are;

The number of students taking the test = The original 453 students

The average change in the test scores, \bar{x}_{1}- \bar{x}_{2} = 9 points

The standard deviation of the change, Δs = 60 points

Therefore, we have;

C.I. = \bar{x}_{1}- \bar{x}_{2} + 1.96 × Δs/√n

∴ C.I. = 9 ± 1.96 × 60/√(453)

i. The 95% confidence interval, C.I. = 3.47467 < μ₁ - μ₂ < 14.52533

ii. Given that both values, the minimum and the maximum limit are positive, therefore, there is no zero (0) within the confidence interval of the difference in of the means of the results therefore, there is statistically significant evidence that students will perform better on their second attempt after the prep course

iii. An experiment that would quantify the two effects is comparing the result of the confidence interval C.I. of the difference of the means when the student had a prep course and when the students had test taking experience

5 0
3 years ago
Please help me on here brainiest for best answer no wrong answers please
julia-pushkina [17]

Answer:

First question is 4,000

Second question is 2000

Step-by-step explanation:

You look at the point at which the graph lines meet and that is how you find you constant of proportionally.

6 0
3 years ago
(Please don't steal points ;-; TY!!!!)Communative property and distrubutive of:
omeli [17]

Answer: okay sure!

Step-by-step explanation:

In mathematics, a binary operation is commutative if changing the order of the operands does not change the result. It is a fundamental property of many binary operations, and many mathematical proofs depend on it.

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7 0
3 years ago
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GEOMETRY- FIND POLYGON AREA
Dvinal [7]

Answer:

Step-by-step explanation:

The area of a regular polygon is

A=\frac{1}{2}ap where a is the apothem and p is the perimeter. Perimeter is simple: just count the number of sides the polygon has and multiply it by 3 (the length of one side).

p = 3(9) is 27 inches for the perimeter.

We have what we need now to find the area:

A=\frac{1}{2}(4.1)(27) and

A=\frac{1}{2}( 110.7) so

A = 55.35 square inches

5 0
2 years ago
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