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-BARSIC- [3]
4 years ago
10

At a concession stand, a pickle and two bags of chips costs a total of $3.25. Three pickles and four bags of chips costs a total

of $7.25. To determine the cost of one pickle, Kevin is writing a system of equations. His first equation is shown below. Which of the following could be the second equation in his system of equations?
Mathematics
1 answer:
kolbaska11 [484]4 years ago
4 0

Answer:

A bag of chips costs $1

A pickle costs $1.25

Step-by-step explanation:

P + 2c = 3.25                            Start with these two equations

3p + 4c = 7.25

p = -2c + 3.25                           Solve for one variable

3(-2c +3.25) + 4c = 7.25           Substitute

-6c + 9.75 + 4c = 7.25

-2c = -2

c = 1

p + 2(1) = 3.25                           Substitute

p + 2 = 3.25

p = 1.25

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we know that

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\frac{32}{180} \frac{cookies}{minutes}= \frac{x}{1} \frac{cookie}{minutes} \\\\x=32/180 \\x=0.18\ cookies

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\frac{0.71}{1} \frac{cookies}{minutes}= \frac{40}{x} \frac{cookie}{minutes} \\\\0.71*x=40\\x=56.34 \ minutes

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The frequency, f, in Hz, at which a simple pendulum rocks back and forth is given by 1 , 2 g f π l = where g is the strength of
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Answer:

a. 0.9 Hz b. 0.37 Hz

Step-by-step explanation:

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a. Find the frequency of a pendulum whose length is 1 foot and where the gravitational field is approximately 32 ft/s2

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So, f =  (1/2π)√(g/l)

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b. The strength of the gravitational field on the moon is about 1/6 as strong as on Earth.. Find the frequency of the same pendulum on the moon.

On the moon when acceleration due to gravity g' = g/6,

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f =  (1/2π)√(g/6l)

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f = (1/2π)√(32/s²)/√6

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f = 0.9/√6 Hz

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