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Blababa [14]
2 years ago
7

Each of the following financial products will help you build credit history EXCEPT

Mathematics
1 answer:
Otrada [13]2 years ago
8 0

Answer:

Each of the following financisl products will help you build a credit history EXCEPT:

Your answer would be Debit card

Step-by-step explanation:

Hope this helps!

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Please please help me! Here is a graph of y=7-x for values x from 0 to 7.
Katen [24]

Answer:

Step-by-step explanation:

hello,

pls find below the graph

we need to find the point of intersection between both lines

which is (4,3)

hope this helps

5 0
3 years ago
Select all polynomials that have (x-3) as a factor.
Alchen [17]

Answer:

Below.

Step-by-step explanation:

Substitute x = 3 into each polynomial and see if the value of the polynomial is zero. If it is zero then x-3 is a factor.

Try number 1:

a(x) = x^3 - 2x^2 - 4x + 3

a(3) = 3^3 - 2(3)^2 - 4(3) + 3

= 27 - 2(9) - 12 + 3

= 27 - 18 - 12 + 3

= 9 - 18 - 9

= 27 - 27

= 0

So a(x) has (x-3) is a factor of a(x)

The other 3 polynomials are solved in the same way.

8 0
2 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
I keep putting in the formula but I keep getting the answer wrong​
Advocard [28]

Answer:

314 in²  (nearest whole number)

Step-by-step explanation:

<u>Radius of a regular polygon</u>: The distance from the <u>center</u> of the polygon to any vertex.  The radius of a hexagon is equal to the length of one side.

Therefore, from inspection of the given diagram:

  • radius = 11 in  ⇒  side length = 11 in

To find the area of a regular polygon, we first need to calculate the apothem.   The <u>apothem</u> is the line drawn from the center of the polygon to the midpoint of one of its sides.

\textsf{Length of apothem (a)}=\dfrac{s}{2 \tan\left(\frac{180^{\circ}}{n}\right)}

where:

  • s = length of one side
  • n = number of sides

Given:

  • s = 11 in
  • n = 6

Substitute the given values into the formula and solve for a:

\implies \textsf{a}=\dfrac{11}{2 \tan\left(\frac{180^{\circ}}{6}\right)}=\dfrac{11\sqrt{3}}{2}

<u>Area of a Regular Polygon</u>

\textsf{A}=\dfrac{n\:s\:a}{2}

where:

  • n = number of sides
  • s = length of one side
  • a = apothem

Given:

  • n = 6
  • s = 11
  • \textsf{a}=\dfrac{11\sqrt{3}}{2}

Substitute the given values into the formula and solve for A:

\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}

\implies \sf A=314.3672216...

\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)

8 0
2 years ago
I know the answer but what’s the work
mina [271]

Answer:

(0.5r^2pi) + (0.5r^2pi) + (bh)

Step-by-step explanation:

All you need to do is to find the area of each shape, then add all areas together.

4 0
3 years ago
Read 2 more answers
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