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likoan [24]
3 years ago
14

PLEASE HELP (30 POINTS)

Mathematics
1 answer:
Oxana [17]3 years ago
8 0

Answer:

O

Step-by-step explanation:

the answer is 0

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A large rectangular area is to be fenced off ( a large rectangle divided into 2 smaller rectangles). The fence used to divide th
Anvisha [2.4K]

Answer:

Length of area is 857.14 ft

Width of area is 857.14 ft

Length of dividing fence is 857.14 ft

Step-by-step explanation:

Here we have

Area of rectangle = Length × Width

The dimension, of the rectangle with the largest area is the dimension of a square, hence we have;

Length of rectangle = Width of rectangle = x

Hence,  the perimeter of the area = 4·x, while the width of the dividing fence = x

Therefore, since the we have;

Cost of the perimeter fence = $15/foot

Cost of the dividing fence = $10/foot

Then;

4·x × 15 + x × 10 = 60000

60·x + 10·x = 60000

x = 60000/70 = 857.14 ft

Which gives the following dimensions;

Length of area = 857.14 ft

Width of area = 857.14 ft

Length of dividing fence = 857.14 ft.

3 0
3 years ago
Which applies the power of a product rule to simplify (5t)^3
Fiesta28 [93]
15t because 5 times 3 its 15
7 0
3 years ago
A kite has a string that is 300 ft long, The flying kite forms a 62°angle with a
anygoal [31]

Answer:

270.9 ft

Step-by-step explanation:

6 + 300sin(62)

= 270.8842779 ft

8 0
4 years ago
QUESTION: Determine if the statement is true or false? if false give an counterexample.
Jobisdone [24]

Answer:

  • False

Step-by-step explanation:

<u>Actual question is:</u>

  • logf 4(3d) + log4 1 = log4 3d

<u>Solution:</u>

  • logf 4 + logf (3d)  + 0 = log4 (3d)
  • logf 4 + logf (3d) = log4 (3d)

<u>If we assume f = 4, then</u>

  • log4 4 + log4 (3d) = log4 (3d)
  • log4 4 = 0

but log4 4 = 1

  • 1 = 0 is impossible

Therefore the statement is False

5 0
3 years ago
There is a 85% probability that Jack's dad gives him permission to go to the movies tonight. There is a 60% chance that he will
xenn [34]

(85 + 60) ÷ 2 = 72.5 Close to 71%

Answer: D - 71%

8 0
3 years ago
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