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Strike441 [17]
3 years ago
10

if two angles are complementary then the sum of their measure is 90. if the sum of the measures of two angles is 90 then both of

the angles are acute.
Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0
Yes, both angles are acute because all complementary angles are acute.
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In the school band, there are 4 trumpet players and F flute players.The total number of trumpet and flute players is 12. Are the
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There is 8 flute players and yes there is twice. Because in total there are 12 instrument players so you could subtract 4 from 12 it will equal 8 and its twice of trumpet players. 
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Please solve. best answer gets rewarded! show step by step answers.
Rina8888 [55]
-17+2(-3)^2
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3 years ago
2x+3=x-4 what is the question
Alex Ar [27]

Answer:

<u>x = - 7</u>

Step-by-step explanation:

Step 1:

2x + 3 = x - 4          Equation

Step 2:

x + 3 = - 4       Subtract x on both sides

Answer:

<u>x = - 7</u>        Subtract 3 on both sides

Hope This Helps :)

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Use the WeierstrassM-test to show that each of the following series converges uniformly on the given domain:
ryzh [129]

Answer:

Step-by-step explanation:

Given a series \sum_{k=1}^\infty f(z), the Weierstrass M-test tell us that if we find a sequence of positive numbers M_n such that |f(z)|\leq M_n in a certain domain D, and the series \sum_{n=1}^\infty M_k converges, then the series \sum_{k=1}^\infty f_k(z) converges uniformly in the domain D.

So, our objective is to find the so called sequence M_k. The main idea is to bound the sequence of functions \frac{z^k}{z^k + 1}.

Now, notice that the values of z are always positive, so z^k is always positive, so z^k+1\geq 1 for all values of z in \overline{D}. Then,

\Big| \frac{z^k}{z^k + 1}\Big| \leq z^k,

because if we make the values of the denominator smaller, the whole fraction becomes larger.

Moreover, as z is in the interval [0,r], we have that z\leq r and as consequence |z^k|\leq r^k. With this in addition to the previous bound we obtain

\Big| \frac{z^k}{z^k + 1}\Big| \leq |z^k|\leq r^k.

With this, our sequence is M_k = r^k and the corresponding series is \sum_{k=1}^\infty r^k, which is a geometric series with ratio less than 1, hence it is convergent.

Then, as consequence of Weierstrass M-test we have the uniform convergence of the series in the given domain.

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3 years ago
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