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blagie [28]
2 years ago
7

g If the quantity of helium in a weather balloon in increased by a factor of 5 at constant temperature and pressure, by how much

does the volume of the balloon change? Decrease by 2 times Increase by 5 times Decrease by 5 times Increase by 2 times
Mathematics
1 answer:
choli [55]2 years ago
6 0

Answer:

Increase by 5 times

Step-by-step explanation:

Given that from the ideal gas law;

PV = nRT

P= pressure

V= volume

n= number of moles

R= gas constant

T = temperature

It the follows that;

V= nRT/P

When the number of moles (quantity of helium) is increased by a factor of 5 while temperature and pressure remain constant, we can write;

PV = 5nRT

V = 5nRT/P

Hence the volume increases by a factor of 5.

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if you have a net spendable income of $1,450 per month, what is the maximum amount of money you should spend on food each month
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The maximum amount of money that should be spent on housing each month is $522.

The maximum amount of money that should be spent on transportation each month is $290.

The maximum amount of money that should be spent on food each month is $246.50.

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7 0
3 years ago
What is the domain and range of y+3=2^x
Bad White [126]

Answer: y>-3 and x is all real numbers


5 0
2 years ago
Given the data 12,39,21,18,24,17,12,25
andreyandreev [35.5K]

Answer:

12,39,21,18,24,17,12,25

Step-by-step explanation:

3 0
2 years ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
The length of RT is 4x-4.Given that point S is between point R and T,
Monica [59]

Answer:

RS = 32

Step-by-step explanation:

Set-up equation like this -- 2x+6+16=4x-4

Solve for x

Then plug x in for the length of RS. You should get 32 for RS.

7 0
3 years ago
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