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Trava [24]
3 years ago
15

Calculate the percent error, with correct sig figs, in the atomic weight if the mass of a Zn electrode increased by 0.3681 g and

6.514x10-3 moles of Zn was produced. Select the response with the correct Significant figures. You may assume the molar mass of elemental zinc is 65.38 g/mol. Refer to Appendix D as a guide for this calculation.
Chemistry
1 answer:
Reptile [31]3 years ago
3 0

Answer:

the percent error is -13.5%  

Explanation:

Given the data in the question;

Exact atomic weight = 65.38 g/mol

For approx

increased mass = 0.3681 g

moles = 6.514 x 10⁻³

we know that; moles = mass / (Atomic mass )

so

Atomic mass__{approx = mass / moles

Atomic mass__{approx  = 0.3681 / 6.514 x 10⁻³

Atomic mass__{approx  = 56.509

so approx atomic weight = 56.51 g/mol

we know that;

% error = ( [approx - exact] / exact ) × 100

we substitute

% error = ( [56.51 - 65.38]  / 65.38 ) × 100

% error = (-8.87 / 65.38 ) × 100

% error = ( -0.1356684 ) × 100  

% error = -13.5%  

Therefore, the percent error is -13.5%  

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Answer:

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Explanation:

(a) The balanced chemical equation for the reaction is

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First, we will determine the different volume of the acids yielded

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From the balanced chemical equation,

1 mole of BrF₅ produces 1 mole of HBrO₃

Likewise, 1 mole of BrF₅ will produce 5 moles of HF

From the question,

5.40×10⁻² moles of bromine pentafluoride (BrF₅) reacted;

Hence, 5.40×10⁻² moles of HBrO₃ will be produced

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From the formula,

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