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valkas [14]
2 years ago
15

True statements:1) deltaH for endothermic reaction is positive3) when the energy is transferred as heat from system to surroundi

ngs, deltaH is negative.6) A combustion reaction is exothermic .False statements:2) deltaH for exothermic reaction is positive. actually it is negative4) when the energy is transferred as heat from surroundings to system, deltaH is negative. actually it is positive5) the evaporation of water is an exothermic process. actually it is an endothermic process.
Chemistry
1 answer:
jeyben [28]2 years ago
5 0

 Answer:

Delta H for endothermic reaction is positive-True. This is because an endothermic reaction absorbs heat energy, therefore more energy is retained inside the product of the reaction system than the reactants, as the value of deltaH is greater than Zero.

Delta H for an exothermic reaction is positive. This is false. Because in an exothermic reaction  heat is liberated to the  surrounding environment. therefore the value of thus the outer environment contains more energy than the internal environments, thus the enthalpy of the reactants is greater than that of the products.

when the energy is transferred as heat from system to surroundings, deltaH is negative. True . This is true because the surrounding environment gain heat energy, (positive)while  the system loses it,(negative) therefore delta H is negative.

when the energy is transferred as heat from surroundings to system, deltaH is negative.  False. This is  positive, because now the environments loses heat, (negative) while the systems gains heat,( positive) therefore delta H of the system is positive. endothermic

the evaporation of water is an exothermic process-False, This is an endothermic reaction in which water molecules need to gain heat energy from the surrounding environments to increase the average kinetic energy  of collusion to escape the intermolecular forces to escape as steam.

Combustion reaction is exothermic. True., because heat energy is transferred to the surrounding from the internal system. The energy needed for the formation  of  new bonds in the products is higher than the energy for breaking of original bonds in the reactants. Thus more heat is liberated.

Explanation:

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The hotter it gets, the faster molecules move, solid form is in low temperature, liquid in medium temperature and gas in high temperature.
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Carbordum is silicon carbide SiC a very hard material used as an abrasive on sand paper and in other applications. it is prepare
AleksandrR [38]

Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

SiO_2+3C\rightarrow SiC+2CO

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = \frac{3000.00 g}{40 g/mol}= 75 mol

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

\frac{1}{1}\times 75 mol=75 mol of silicon dioxide.

mass of 75 moles of silicon dioxde:

75 mol\times 60 g/mol=4500 g=4.5 kg

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

3 0
3 years ago
What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, c2h6? in this reaction,
Vitek1552 [10]

Balance equation for combustion of ethane will be:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

To balance the equation:

1. Balance the number of carbon atom on both side:

C₂H₆(g) + O₂(g)--------> CO₂(g) + H₂O(g)

1. balance the number of carbon on both side, as in reactant there are 2 but in product one,

so , multiply the CO₂, by 2 in the product.

2. Balance the number of hydrogen on both side as in reactant the number of hydrogen is 3 but in product it is 6 so, multiplythe number of  H₂O by 3,

so multiply the number of  H₂O by 3 in product.

3. Balance the number of oxygen on both side , as 1 and 2 step increases the number of oxygen and it becomes 7 , so to balance the number of oxygen on both side by mutiplying the  number of  O₂ by 7/2 in reactant .

4. Now, doubling the equation will give balance equation that is:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

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3 years ago
Use kinetic molecular theory to explain why a gas takes the shape and volume of its container
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Answer:

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7 0
3 years ago
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Here we have to complete the given single replacement reactions.

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1) Fe (s) + CuCl₂ (aq) → FeCl₂ (aq) + Cu (s)

2) Cu (s) + FeCl₂ (aq) → NA

3) K (s) + NiBr₂ (aq) → NA

4) Ni (s) + KBr (aq) → NiBr₂ (aq) + K (s)

5) Zn (s) + Ca(NO₃)₂ (aq) → Zn(NO₃)₂ (aq)  + Ca (s)

6) Ca (s) + Zn(NO₃)₂ (aq) → NA

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We know the half cell reactions in which the standard reduction potentials are positive are allowed.

1) The reaction is possible as Cu²⁺/Cu and Fe/Fe²⁺ standard reduction potentials are positive.

2) The reaction is not possible as Cu/Cu²⁺ and Fe²⁺/Fe standard reduction potentials are negative.

3) The reaction is not possible as Ni²⁺/Ni standard reduction potential is negative.

4) The reaction is possible as Ni/Ni²⁺ standard reduction potential is positive.

5) The reaction is possible as Zn/Zn²⁺ standard reduction potential is positive.

6) The reaction is possible as Zn²⁺/Zn standard reduction potential is negative.

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2 years ago
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