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Marina86 [1]
3 years ago
5

Solve the equation with the quadratic formula 4k^2-11k-18=0

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Quadratic formula tells us that the roots are equal to:

\frac{-b\pm \:\sqrt{b^2-4ac}}{2a}

The letters are just the coefficients, so a = 4, b = -11, and c = -18. Plugging these values into the formula we get:

\frac{-11\pm \sqrt{11^2-4\cdot \:4\left(-18\right)}}{2\cdot \:4}

Which when simplified tells us that the roots are:

\frac{-11+\sqrt{409}}{8} or \frac{-11-\sqrt{409}}{8}

Remember the plus or minus sign is what gives us two answers.

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An aquarium 2 m long, 1 m wide, and 1 m deep is full of water. Find the work (in J) needed to pump half of the water out of the
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Answer:

W=2452.5 J

Step-by-step explanation:

The work is define as the integral of the force times distance. So we have:

W=\int^{a}_{b}Fxdx

Now, we can write the force in terms of density.

F=m*g=\rho Vg

V is the volume (V=2*1*1=2 m³)

So the work will be:

W=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0}19620xdx=19620(\frac{x^{2}}{2})|^{0.5}_{0}

The limit of integration is between 0 and 0.5 because we want to pump half of the water out of the aquarium.

W=19620(\frac{x^{2}}{2})|^{0.5}_{0}=19620(\frac{0.5^{2}}{2})

W=2452.5 J

I hope it helps you!

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