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Paha777 [63]
3 years ago
14

Math question can you please help and can you breakdown how you got your answer

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

8

Step-by-step explanation:

AB=DC

BC=AD

BA=CD

CB=DA

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Identify all of the following solutions of square root of x minus 8 end root plus 8 equals x.
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\sqrt{x-8} +8=x \\  \sqrt{x-8} =x-8 \\  {( \sqrt{x-8} )}^{2} = {(x-8)}^{2}  \\ x-8= x^{2} -16x+64 \\  x^{2} -16x-x+64+8=0 \\  x^{2} -17x+72=0

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4 0
3 years ago
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Y=-4x-7, x+y=2 please help rn
Mashcka [7]
Use substitution
x -4x - 7 = 2
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Solution: x = -3, y = 5
5 0
3 years ago
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