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3 years ago

What are the coordinates for the point on this grid? Enter your answer.

Mathematics

2 answers:

liberstina [14]3 years ago

7 0

Answer:

(3, 6)

Step-by-step explanation:

oee [108]3 years ago

3 0

Answer:

(3,6)

Step-by-step explanation:

If you start at 0, you move 3 units left, and 6 units up.

Hope it helps :))

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What are the square roots of 121? Select two answers from the choices below.

zhannawk [14.2K]

Answer:

No image or answer choices

Step-by-step explanation:

6 0

3 years ago

a bricklayer needs to order 6300kg of building sand.one grain of this sand weighs 7x10^-5. how many grains of sand are there in

gavmur [86]

Answer:

44.1 x 10^-2

Step-by-step explanation:

Since one grain

= 7 x 10^-5

6300kg = 7 x 10^-5 x 6300

Put 6300 in standard form

7 x 10^-5 x 6.3 x 10^3

Multiply the whole numbers and add the exponents

7 x 6.3 x 10^-5 + 3

44.1 x 10^-2

There are 44.1 x 10^-2 grains of sand in 6300kg

5 0

3 years ago

Tan(a)+cot(b) simplify please.

Hitman42 [59]

Answer:

tan a + cot b

Step-by-step explanation:

It's already simplified.

There are alternate forms like

$sec(a)csc(b)cos(a-b)\\\\sec(a)csc(b)[sin(a)sin(b)+cos(a)cos(b)]\\\\\frac{sin (a)}{cos (a)} +\frac{cos(b)}{sin(b)}$

5 0

3 years ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

For Bus:

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

For motorcycle:

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago

Polynomial 5x^5-9x^3+2x^11+6

tresset_1 [31]

So we have a polynomial 5x^5-9x^3+2x^11+6 and we are wondering what is its degree, leading coefficient, number term and the constant term. The degree of a polynomial is its highest power so here that is 11. Leading coefficient is the term with the highest degree of a polynomial and here thats 2. Number of terms is 4 because that many numbers are in this polynomial and the constant term is 6 beccause it is a constant.

3 0

3 years ago