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3 years ago

What is the relationship between APB and minor arc AB?

Mathematics

1 answer:

Dmitry [639]3 years ago

4 0

Answer:

Step-by-step explanation:

If APB is measured in radians, then the arc length AB = APB(r) where r is the radius of the circle.

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Jamie ordered 200 business cards and paid $23. She ordered 500 business cards and few months later and paid $35. WRITE and SOLVE

Karo-lina-s [1.5K]

Find the unit rate of the previous two. use that to plug in 700

8 0

3 years ago

Use the given parent function f(x)=|x| to graph g(x)=|x+2|-4. use the ray tool and select two points to graph each ray.

marin [14]

Shown in the attached figure

<h2>Explanation:</h2>

The absolute value function is a function that takes the shape of a V. The pattern of the absolute value function is:

$f(x)=\mid x \mid$

So we need to use this function in order to obtain:

$g(x)=\mid x+2 \mid -4$

Recall that to translate a function vertically, we use the following rule:

$g(x)=f(x)+k \\ \\ \bullet \ If \ k>0 \ the \ graph \ of \ f(x) \ is \ translated \ k \ units \ up \\ \\ \bullet \ If \ k$

And to translate a function horizontally, we use the following rule:

$g(x)=f(x+c) \\ \\ \bullet \ If \ c>0 \ the \ graph \ of \ f(x) \ is \ translated \ c \ units \ to \ the \ left \\ \\ \bullet \ If \ c$

Since:

$c=2>0 \ and \ k=-4$

Then:

<em>g(x) is the translation of f(x) 2 units to the left and 4 units down</em>

<em />

<h2>Learn more:</h2>

Transformations in real-world problems: brainly.com/question/1033817

#LearnWithBrainly

8 0

3 years ago

Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.

Softa [21]

Answer:

4i.

Step-by-step explanation:

To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA

F(x,y) = hxy,x - yi

div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i

So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA

= ∫∫(hy - i).dxdy

= ∫∫hydxdy - ∫∫idxdy

Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then

∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy

= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx

= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx

= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx

= 0 - i∫₋₁¹2dx

= - 2i[x]₋₁¹

= 2i[1 - (-1)]

= 2i[1 + 1]

= 2i(2)

= 4i

7 0

3 years ago

Phoebe, andy and polly share €270

jeka94

Answer:

Polly=30

Andy=60

Phoebe=180

Step-by-step explanation:

Polly=x

Andy=2x

Phoeby 3(2x)=6x

x+2x+6x=270

9x=270

x=30

Polly=x=30

Andy = 2x=60

Phoebe=6x=180

7 0

3 years ago

The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The par

kicyunya [14]

Answer:

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

$fi*P(x$

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

$P( z \leq \frac{c-1-12}{3.5}) =0.99/fi$

solving for "c", knowing that fi is a tabulating value:

$\frac{c-13}{3.5}=0.99/fi\\\frac{c-13}{3.5}=2.33\\c-13=2.33*3.5\\c = 8.155 +13\\c = 21.155$

therefore the value of c is equal to 21.16

8 0

3 years ago