-2 or -2/1 because the ratio is y over x and the line is going down 2 (-2) every time it goes to the right once (1)
The question is incomplete.
This is the complete question as I found in internet:
<span>Use substitution to determine which of the following points is a solution to the standard form equation below 5x-2y = 10
these are the points:
</span>
-1,5
1,5
0,-5
0,5
Answer: (0, -5)
Explanation:
point x y 5x - 2y = 10 ?
-1,5 -1 5 5(-1) - 2(5) = - 5 - 10 = - 15 ≠ 10 ⇒ not a solution
1,5 1 5 5(1) - 2(5) = 5 - 10 = 5 ≠ 10 ⇒ not a solution
0,-5 0 -5 0 -2(-5) = 10 ⇒ a solution
0,5 0 5 0 - 2(5) = - 10 ≠ 10 ⇒ not a solution
Answer:
I think it might be A: 75< x<84
Step-by-step explanation:
but i am not sure
Answer:
1. 155 yd², 2. 379.54 ft², 5. x = 65.82π
Step-by-step explanation:
1. A = (1/2) · (3 + 13) · 8
A = (1/2)(16)(8)
A = 64
A = bh
A = 13*7
A = 91
64 + 91 = 155
155 yd²
2. A = bh
A = 25x25
A = 625
A = πr²
A = 3.14*12.5²
A = 3.14*156.25
A = 490.625
490.925/2 = 245.4625
625 - 245.4625 = 379.5375
379.54 ft²
3. and 4. Sorry, I don't know how to solve these
5. A = πr²
A = 3.14*7²
A = 3.14*49
A = 153.86
x/154 = 153.86π/360
360x = 154*153.86π
360x = 23694.44π
x = 65.8178889π
x = 65.82π
Hope this helps :)
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
