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Elena L [17]
3 years ago
14

Compare the functions below: Which function has the smallest minimum?

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

D. All three functions have the same minimum value

Step-by-step explanation:

f(x) = -3 sin (x-pi) +2

Sin has a minimum value of -1, but since it is multiplied by a negative, we want its maximum value

sin has a maximum of 1

f (min) = -3(1) +2 = -1

g(x) has a minimum at x =3  

g(minimum) = -1

h(x) = (x+7)^2 -1

        The smallest a squared value can be is zero

     = 0 -1

h(min) =-1

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Answer:

A

Step-by-step explanation:

Recall that for a quadratic equation of the form:

0=ax^2+bx+c

The number of solutions it has can be determined using its discriminant:  

\Delta = b^2-4ac

Where:

  • If the discriminant is positive, we have two real solutions.
  • If the discriminant is negative, we have no real solutions.
  • And if the discriminant is zero, we have exactly one solution.

We have the equation:

2x^2+5x-k=0

Thus, <em>a</em> = 2, <em>b</em> = 5, and <em>c</em> = -<em>k</em>.

In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:

b^2-4ac=0

Substitute:

(5)^2-4(2)(-k)=0

Solve for <em>k</em>. Simplify:

25+8k=0

Solve:

\displaystyle k = -\frac{25}{8}

Thus, our answer is indeed A.

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2 years ago
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Answer:

-17/12

Step-by-step explanation:

-(2/3)-(3/4)

-(8/12)-(9/12)

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Step-by-step explanation:

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