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2 years ago

5

What is this equation 4(3+5)- 3.9*2 THIS ISN´T A DECIMAL ITS A MIDDLE DOT

1 answer:

vredina [299]2 years ago

4 0

Answer:

The answer is letter 'J'

Step-by-step explanation:

4(3+5) - 3 x 9^2

4(8) - 3 x 9^2 ← 9 x 9 = 81

16 - 3 x 9^2

16 - 3 x 81

13 x 81

1,053

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What is the base 8 representation of 112

Andreas93 [3]

Solution Step1 Converting 112 to base 10.
1*82=64
1*81=8
2*80=2
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2|74
2|37|0
2|18|1
2|9|0
2|4|1
2|2|0
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<span>Ans:10010102</span>

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3 years ago

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Maria mows 2/3 of a lawn in 1/5 hour. How Many similar-sized lawns can she mow in 1 hour?

sp2606 [1]

Answer:

10/3 lawn

Step-by-step explanation:

2/3 of a lawn in 1/5 hour

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7 0

3 years ago

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you want to create a 99 confidence interval with a margin of error of 25 assuming that the population standard deviation is equa

Ahat [919]

Answer:

The minimum sample size is 239.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Population standard deviation is equal to 1.5

This means that $\sigma = 1.5$

Margin of error of 0.25

This means that $M = 0.25$

What's the minimum size of the sample?

$M = z\frac{\sigma}{\sqrt{n}}$

$0.25 = 2.575\frac{1.5}{\sqrt{n}}$

$0.25\sqrt{n} = 2.575*1.5$

$\sqrt{n} = \frac{2.575*1.5}{0.25}$

$(\sqrt{n})^2 = (\frac{2.575*1.5}{0.25})^2$

$n = 238.7$

Rounding up:

The minimum sample size is 239.

4 0

3 years ago

Can anyone please help with this.

Eddi Din [679]

The first question answer is 21*10^7
The second question answer is 5*10^2

7 0

3 years ago

Find the distance between (-2, 8) and (11, 2). Round to the nearest hundredth.

MakcuM [25]

Answer:

14.32

Step-by-step explanation:

We can find the distance using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We then substitute (-2,8) as $(x_1,y_1)$ and (11,2) as $(x_2,y_2)$ .

$d=\sqrt{(11--2)^2+(2-8)^2} \\d=\sqrt{(13)^2+(-6)^2} \\d=\sqrt{169+36}\\d=\sqrt{205}=14.32$

6 0

3 years ago