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insens350 [35]
4 years ago
7

mya has ballet lessons every sixth day and swimming every fourth day. today she has both lessons. in how many days will mya have

both lessons on the same day again?
Mathematics
1 answer:
ra1l [238]4 years ago
5 0
To determine when Mya will have both lessons again on the same day, you will list the multiples of each number of days because to show every 4 or 6 days, you will count by 4's and 6's.

When you get to the first number that is the same, that will be the next time she will have both lessons again.  This is called the least common multiple (LCM).

4, 8, 12, 16, 20, ...
6, 12, 18, 24

In 12 days she will have both lessons again.
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Expand to write an equivalent expression: 4(-8x+6y)
Naddika [18.5K]

Answer:

-32x + 24y

Step-by-step explanation:

4(-8x + 6y) ⇒ -32x + 24y

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti
ElenaW [278]

Answer:  \bold{w=\dfrac{6y-3}{2}}

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

  • Multiply by 6 on both sides to clear the denominator
  • Subtract 3 from both sides
  • Divide both sides by 2

y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}

5 0
3 years ago
How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on
Mariulka [41]

Combinations = n! / (n - r)! r!

C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements

7 0
1 year ago
Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo
eduard

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins)   $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12    

+ 16 dimes     $1.60

Total Coins 48      $4.32

8 0
3 years ago
What is the value of y?​
romanna [79]

Answer:

60

Step-by-step explanation:

y+y+60=180

2y =120

therefore,y=60

7 0
3 years ago
Read 2 more answers
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