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Helen [10]
3 years ago
14

el precio de la mochila que compró Juan e 18,500 una tienda la ofreció en 2 centenas más qué precio tenía ​

Mathematics
1 answer:
sweet [91]3 years ago
3 0

Answer:

18,502 no se no entendi muy bien

Step-by-step explanation:

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Where is the diagram????????

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3 years ago
A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be,
Iteru [2.4K]
The starting value is 20,300, and the value is decreasing by 9.5% each year.

Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.

A decrease by 9.5% corresponds to multiplying by 91.5% each year.

We write . We plug in 11 years for t.

A(t)=23000(0.915)^{t}\\\\A(11)=23000(0.915)^{11}\\\\A(11)=7671.18

$7,671.18
6 0
3 years ago
Melons cost $20 pet Crate, and apples cost $8 per create. an order comes in for a total of 48 crates for $420. what was the numb
Alika [10]

Answer:

The number of melon was 3 and the number of apples was 45.

Step-by-step explanation:

1. Melons cost $20 per crate and apples cost $8 per create. If the total was 48 crates for $420, you can make the following system of equations, where x is the number of melons and y is the number of apples:

\left \{ {{x+y=48} \atop {20x+8y=420}} \right.

2. By applying the Method of substitution, you can solve for y in the first equation and substitute it into the second one to find x. Then, you can substitute the value of x into the first equation to find y:

y=48-x

20x+8(48-x)=420\\20x+384-8x=420\\12x=36\\x=3

3+y=48\\y=45


4 0
3 years ago
Which table shows equivalent times in minutes and seconds
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8 0
3 years ago
Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p
frutty [35]

Answer:

y = 0.00587x +1986.406

Step-by-step explanation:

Given that the population of a city increased steadily over a ten-year span. The following ordered pairs show the population x and the year y over the ten-year span in the form (x, y) for specific recorded years.

x y

 

2500 2001

2650 2002

3000 2004

3500 2007

4200 2011

 

 

Slope 0.005865485

Intercept 1986.406413

So regression line is

y = 0.00587x +1986.406

When population = 15000

0.00587(17000)+1986.406\\=2074.389

3 0
3 years ago
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