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GarryVolchara [31]
4 years ago
12

I NEED HELP AS SOON AS POSSIBLE!

Mathematics
1 answer:
Masja [62]4 years ago
7 0
Think of it this way:

You are trying to make a ratio to the months with thirty days and the ones who don't.

So,

there are 4 months a year with 30 days.

That means that there are 12-4= 8 months a year that are not 40 days.

It said the months to 30 days first in the problem.

4:8

Divide each side by 4, since both are divisible by 4.

1:2

For every one month of 30 days, there are 2 months that do not have 30 days.

1 to 2 is your answer.

I hope this helps!
~kaikers
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An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B. Eight random graduates from c
Karolina [17]

Answer:

Calculated value t =  0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

<u>Step-by-step explanation:</u>

<u>we will t-test </u> t = x⁻- y⁻ /S√ n₁+n₂-2

Given An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B

course A type at 62, 85, 59, 64, 73, 70, 75, and 72

mean of x is x⁻ = ∑x / n

mean of x = 62+85+59+64+73+70+75+ 72 /8 = 70

x⁻ = 70

course B type at 75, 64, 81, 55, 69, and 58

mean of y is  y⁻ = ∑y / n = 75+64+81+55+69+ 58/6 = 67

y⁻ =67

course A    course B

    x                    y             x- x⁻     (x-x⁻ )^2     y- y⁻     (y-y⁻ )^2    

    62                75            8             64          8            64

    85                64           15            225       -3             9

    59                81           -11            121          14            196      

    64                55           -6            36          -12          144          

    73                69          3                9            2            4

    70               58            0              0           -9            81

    75                              5              25

    72                              2               4

                                            ∑( (x-x⁻ )^2= 484           ∑( (y-y⁻ )^2= 498

Adding ∑( (x-x⁻ )^2+ ∑( (y-y⁻ )^2= 982

n₁+n₂-2 = 8+6-2=12

now S^2 =  982/ 12 =81.833

<u>Null hypothesis :H₀:μ₁=μ₂ ( there is no difference between A and B)</u>

<u>Alternative hypothesis :H₁:μ₁≠μ₂</u>

<u>level of significance ∝=0.05</u>

<u>we will use t-test </u> t =   0.614 ( see attachment )

The degrees of freedom = n₁+n₂-2 = 8+6-2=12

From tabulated value  t = 1.782

Calculated value t = 0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

There is no difference between Course A and Course B

Download docx
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