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astraxan [27]
3 years ago
15

Cara has $25 to buy dry pet food a pound of dog food costs $2 and treats are $1 apiece if she buys 9 pounds of food the greatest

number treats does know
Mathematics
1 answer:
zzz [600]3 years ago
5 0

Cost of each pound of dog food = $2 .

Total cost of 9 pounds of dog food = 9 * 2 = $18.

Let us assume number of treats she can buy = t.

Cost of each treat = $1.

Cost of t number of treats = 1*t = 1t .

Total money Cara has = $25.

We can setup an inequality as,

Total cost of dog food + total cost of t number of treats ≤ 25.

18 + 1t ≤ 25.

Subtracting 18 from both sides, we get

18 + 1t -18  ≤ 25-18.

1t ≤ 7 or t ≤ 7.

So, she can purchase 7 or less treats.

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Read 2 more answers
A meeting on an unpopular topic has been announced. The number of attendees may be modeled by X where What is the probability th
krok68 [10]

Answer:

The probability that at least 5 people attend the meeting given that at least 2 attend is 12.50%.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

A meeting on an unpopular topic has been announced. The number of attendees may be modeled by X where:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,...

What is the probability that at least 5 people attend the meeting given that at least 2 attend?

The explanation of the answer is now provided as follows:

Given:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,...                    (1)

Since it is given that at least 2 attend, it implies that we need to calculate P(x) at x = 2.

Substituting x = 2 into equation (1), we have:

P(X = 2) = 1 / 2^(2 + 1)

P(X = 2) = 1 / 2^3

P(X = 2) = 1 / 8

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3 years ago
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<span>We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:
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i) 2x + 2y = 8

ii) x + y = 4
<span>
use equation ii) to write y in terms of x as : y=4-x, 

substitute y =4-x in equation i):

</span>2x + 2y = 8
2x + 2(4-x) = 8
<span>2x+8-2x=8
8=8

this is always true, which means the equations have infinitely many common solutions.


Answer: </span><span>There are infinitely many solutions.</span><span>

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