ANSWER
EXPLANATION
We use the sine rule for solving triangles.
This is given by the formula,
From the triangle,
We multiply both sides of the equation by 60 to get,
We solve for x to obtain,
To the nearest tenth, we round to one decimal place to get,
Answer:
0.84
Step-by-step explanation:
1 - 0.4(0.4) = 1 - 0.16 = 0.84
Simply take the probability of the the outcome that is not " at least 1 win", which is the probability of 2 losses;
To find the probability multiply the probabilities along the branches.
Answer:
56.25%
Step-by-step explanation:
800 - 350 = 450
1% of 800 = 8 (800 divided by 100)
450 divided by 8 = 56.25
Answer:
81.85%
Step-by-step explanation:
We have the following information:
mean = m = 52000
standard deviation = sd = 12000
a = 40000
b = 76000
we need to find the probability between a and b, that is:
P (a <x <b) = P (40,000 <x <76000)
P [(40000 - m) / sd <(x - m) / sd <(76000 - m) / sd]
replacing
P [(40000 - 52000) / 12000 <z <(76000 - 52000) / 12000]
P (-1 <z <2)
P (z <= -1) - P (z <= 2)
We look for this value of z, in the attached table:
0.9772 - 0.1587
P = 0.8185
In other words, the probability is 81.85%
Answer: D
<u>Step-by-step explanation:</u>
The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.
![\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D2x-y%5C%5Cx-6y%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
The product will result in the solution for the x- and y-values of the system.
