Answer:
(f + g)(x) = I2x + 1I + 1 ⇒ C
Step-by-step explanation:
Let us solve the question
∵ f(x) = I2x + 1I + 3
∵ g(x) = -2
→ We need to find (f + g)(x), which means add the two functions
∵ (f + g)(x) = f(x) + g(x)
→ Substitute the right side of each function on the right side
∴ (f + g)(x) = I2x + 1I + 3 + (-2)
→ Remember (+)(-) = (-)
∴ (f + g)(x) = I2x + 1I + 3 - 2
→ Add the like terms in the right side
∵ (f + g)(x) = I2x + 1I + (3 - 2)
∴ (f + g)(x) = I2x + 1I + 1
Answer:
<h3>4th answer is correct</h3>
Step-by-step explanation:
Answer:
D. 10:4 and 5 to 2
Step-by-step explanation:Hope you get it right :)
Answer:
4
Step-by-step explanation:
just ÷ 5 into 23 and just took 4 from 4.6 then ÷ 4into 16= 4
