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taurus [48]
2 years ago
12

Dxcfgvbhjnkmlnjhcgfdxzs

Mathematics
2 answers:
bearhunter [10]2 years ago
8 0

Answer:

D

Step-by-step explanation:

The increase in temperature can be calculated using the absolute value of the difference of the two numbers. The absolute value is the positive value of whatever is inside of the two symbols, |       |.

We can check this by seeing that at midnight the temperature was -8, and at noon it was 23. Therefore, the temperature increased 23+8 degrees which is 31.

| -8-23 | = 31, which allows us to see that D is the correct answer

Bogdan [553]2 years ago
6 0

Answer:

D

Step-by-step explanation:

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Is the following expression true or false? Show your work.
Paul [167]

Answer: True

Solution:

Rearrange the equation to the LHS:

[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0

Factoring  x^2+8x+16

x^2 - 4x - 4x - 16

= (x-4)  •  (x-4)

= = (x+4)2

So now we have an equation

(x + 4)^2 • (x - 4)^2 -  (x^2 - 16)^2  = 0

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3 0
3 years ago
A 30-N stone is dropped from a height of 10 m and strikes the ground with a speed of 13 m/s.
Anon25 [30]

Answer:

4.1 N

Step-by-step explanation:

We can solve this problem by using considerations about energy.

At the moment the stone is dropped, it has only gravitational potential energy:

PE=mgh

where

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h = 10 m is the initial height of the stone

As the stone falls, part of this energy is converted into kinetic energy, while part into thermal energy due to the presence of the air friction, acting opposite to the motion of the stone:

KE+E_t = \frac{1}{2}mv^2 + E_t

where:

m=\frac{mg}{g}=\frac{30}{9.8}=3.06 kg is the mass

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E_t is the thermal energy

The thermal energy is actually equal to the work done by the air friction on the stone:

E_t=W=Fh

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F is the average force of friction

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Since the total energy must be conserved, we can combine the three equations, so we find:

mgh=\frac{1}{2}mv^2+Fh

And solving for F, we find the average force of air friction:

F=\frac{mgh-0.5mv^2}{h}=\frac{(30)(10)-0.5(3.06)(13)^2}{10}=4.1 N

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2 years ago
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