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3 years ago

9

A jar contains 900 beans. Of all the beans 2/3 are azuki beans and the rest are Lima beans. What is the ratio of azuki beans to

Lima beans

1 answer:

serg [7]3 years ago

7 0

Answer:

2:1

Step-by-step explanation:

There are 600 azuki beans and 300 Lima beans. 600/300 simplified is 2:1 :DD

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Kitty [74]

Answer:

5. -5x - 1

6. -x - 4

Step-by-step explanation:

5.

Distribute (get rid of parentheses):

-5x - 1

6.

Distribute (get rid of parentheses):

-x - 4

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3 years ago

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Choose as many answers as apply. Which of the following are metric measurements? gallon liter meter pint quart kilogram kilowatt

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Liter
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3 years ago

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sveta [45]

Answer:

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Step-by-step explanation:

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2 years ago

I need help with this math equation?

Licemer1 [7]

Step-by-step explanation:

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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2 years ago