Answer: a. 0.14085
b. 3.826 x 
c. 0.5437
d. 0.0811
Step-by-step explanation:
Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , 
= $527
Given standard deviation , 
= $160
Let X = amount spent on a randomly selected child
Also Z = 
a. Probability(X>$700) = P( > 
) = P(Z>1.08125) = 0.14085 {Using Z % table}
b. P(X<100) = P( Z < 
) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x
c. P(450<X<700) = P(X<700) - P(X<=450)
P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592
P(X<=450) = P(Z<= 
) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155
So final P(450<X<700) = 0.8592 - 0.3155 = 0.5437
d. P(X<=300) = P(Z<= 
) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811
All the above probabilities are calculated using Z % table along with interpolation between two values.
Answer:
B
Step-by-step explanation:
208 divided by 6.4 = 32.5
Answer:
The number of pounds of cashew is 11
Step-by-step explanation:
Let P represent the peanut
Let C represent the cashew nut.
From question, we were told that Elijah brought a total of 16 pounds of peanuts and cashew nuts. This can be written as:
P + C = 16 (1)
The total cost = $49.50
Cost per peanut = $2.75
Cost per cashew = $3.25
The above can be represented as:
49.50 = 2.75P + 3.25C. (2)
From equation 1,
P + C = 16
P = 16 — C
Substitute the value of P into equation 2:
49.50 = 2.75P + 3.25C.
49.50 = 2.75(16 — C) + 3.25C
49.50 = 44 — 2.75C + 3.25C
49.50 = 44 + 0.5C
Collect like terms
49.50 — 44 = 0.5C
5.5 = 0.5C
Divide both side by 0.5
C = 5.5/0.5
C = 11
Therefore, the number of pounds of cashew is 11
Answer:
0.45454545454, also known as 0.45 repeated
Step-by-step explanation:
