![(x+5)(x-3)[x-(4-i)][x-(4+i)] \\ (x^{2}+5x-3x-15)(x-4+i)(x-4-i) \\ (x^{2}+5x-3x-15)(x^{2} -4x-xi-4x+16+4i+xi-4i- i^{2} ) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16- i^{2}) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16-(-1)) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16+1) \\ (x^{2}+5x-3x-15)( x^{2} -8x+17)](https://tex.z-dn.net/?f=%28x%2B5%29%28x-3%29%5Bx-%284-i%29%5D%5Bx-%284%2Bi%29%5D%0A%20%5C%5C%20%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x-4%2Bi%29%28x-4-i%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x%5E%7B2%7D%20-4x-xi-4x%2B16%2B4i%2Bxi-4i-%20i%5E%7B2%7D%20%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%20i%5E%7B2%7D%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%28-1%29%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16%2B1%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B17%29)
From there just distribute and simplify.
Answer:
22.5 cm^2
Step-by-step explanation:
Amount of paper is going to be measured in area, so we want the surface area of the cone. Since it is a cub it doesn't have a base, so we don't need to count it.
Area of the cone without the base, or what is called the lateral area is pi*r*s where r is the radius and s is the slant height. and of course radius is d/2 where d is the diameter. so let's plug it in. We know diameter is 6 and slant height is 7.5
SA = pi * r * s
SA = pi * d/2 * s
SA = pi * 6/2 * 7.5
SA = 22.5 cm^2
So you will need 22.5 square centimeters of paper.
No, because in the first one the 4 is negative, in the second it is positive
5/9 or 0.5 recurring
hope this helps :)
