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Yanka [14]
3 years ago
15

A total of 600 advertisements were sold for a certain magazine. If 30 percent of the first 200 sold were in color, 20 percent of

the next 300 sold were in color, and 90 percent of the last 100 sold were in color, what percent of the 600 advertisements were in color?
Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

%35 of them were in color

Step-by-step explanation:

Since 30 percent of the first 200 sold were in color, 200x30/100 = 60 of them were in color.

Since 20 percent of the next 300 sold were in color, 300x20/100 = 60 of them were in color.

Since 90 percent of the last 100 sold were in color, 100x90/100 = 90 of them were in color.

In total, 60 + 60 + 90 = 210 out of 600 were in color.

The percentage is:  \frac{600}{100} = \frac{210}{x} → x = \frac{21000}{600} = 35

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Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

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Significance level : \alpha= 1-0.98=0.02

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Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

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Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

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3 years ago
What is the measure of ∠S ?
jeka94

Alright, lets get started.

We could use sine law to find the remaining angle.

\frac{sinA}{a} =  \frac{sinB}{b}

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Plugging the value of sin 64

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Hope it will help :)



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